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112044041100403 = 611836787559023
BaseRepresentation
bin11001011110011101001001…
…010001001101110001110011
3112200201022020212111100011221
4121132131021101031301303
5104141212144010203103
61034144153310245511
732412625534302346
oct3136351121156163
9480638225440157
10112044041100403
113277867a245615
1210696a767b6897
134a69927b9a149
141d94d6397045d
15ce47c8d6a1bd
hex65e74944dc73

112044041100403 has 4 divisors (see below), whose sum is σ = 113880828659488. Its totient is φ = 110207253541320.

The previous prime is 112044041100349. The next prime is 112044041100449. The reversal of 112044041100403 is 304001140440211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 112044041100403 - 229 = 112043504229491 is a prime.

It is a super-2 number, since 2×1120440411004032 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (112044041100703) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 918393779451 + ... + 918393779572.

It is an arithmetic number, because the mean of its divisors is an integer number (28470207164872).

Almost surely, 2112044041100403 is an apocalyptic number.

112044041100403 is a deficient number, since it is larger than the sum of its proper divisors (1836787559085).

112044041100403 is an equidigital number, since it uses as much as digits as its factorization.

112044041100403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1836787559084.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 112044041100403 its reverse (304001140440211), we get a palindrome (416045181540614).

The spelling of 112044041100403 in words is "one hundred twelve trillion, forty-four billion, forty-one million, one hundred thousand, four hundred three".

Divisors: 1 61 1836787559023 112044041100403