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112100122131 = 337366707377
BaseRepresentation
bin110100001100110110…
…0000001111000010011
3101201100110011020100020
41220121230001320103
53314040112402011
6123255330354523
711045642213334
oct1503154017023
9351313136306
10112100122131
11435a5661a38
121988612ba43
13a75662b51a
1455d60a228b
152db1686006
hex1a19b01e13

112100122131 has 4 divisors (see below), whose sum is σ = 149466829512. Its totient is φ = 74733414752.

The previous prime is 112100122097. The next prime is 112100122157. The reversal of 112100122131 is 131221001211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 112100122131 - 231 = 109952638483 is a prime.

It is a super-2 number, since 2×1121001221312 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 112100122131.

It is not an unprimeable number, because it can be changed into a prime (112100121131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18683353686 + ... + 18683353691.

It is an arithmetic number, because the mean of its divisors is an integer number (37366707378).

Almost surely, 2112100122131 is an apocalyptic number.

112100122131 is a deficient number, since it is larger than the sum of its proper divisors (37366707381).

112100122131 is an equidigital number, since it uses as much as digits as its factorization.

112100122131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37366707380.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 112100122131 its reverse (131221001211), we get a palindrome (243321123342).

The spelling of 112100122131 in words is "one hundred twelve billion, one hundred million, one hundred twenty-two thousand, one hundred thirty-one".

Divisors: 1 3 37366707377 112100122131