Base | Representation |
---|---|
bin | 1010001100100000100101… |
… | …0001011010011000011101 |
3 | 1110200200000120201100212220 |
4 | 2203020021101122120131 |
5 | 2432131110132431023 |
6 | 35501451233215553 |
7 | 2234616515352303 |
oct | 243101121323035 |
9 | 43620016640786 |
10 | 11210020202013 |
11 | 36321631831a6 |
12 | 13106b11015b9 |
13 | 63413c684a39 |
14 | 2aa7d4358273 |
15 | 1468e967c3e3 |
hex | a320945a61d |
11210020202013 has 8 divisors (see below), whose sum is σ = 15200027392800. Its totient is φ = 7346679906288.
The previous prime is 11210020201979. The next prime is 11210020202023. The reversal of 11210020202013 is 31020202001211.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11210020202013 - 221 = 11210018104861 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11210020201983 and 11210020202001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11210020202023) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31666723558 + ... + 31666723911.
It is an arithmetic number, because the mean of its divisors is an integer number (1900003424100).
Almost surely, 211210020202013 is an apocalyptic number.
It is an amenable number.
11210020202013 is a deficient number, since it is larger than the sum of its proper divisors (3990007190787).
11210020202013 is an equidigital number, since it uses as much as digits as its factorization.
11210020202013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 63333447531.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 11210020202013 its reverse (31020202001211), we get a palindrome (42230222203224).
The spelling of 11210020202013 in words is "eleven trillion, two hundred ten billion, twenty million, two hundred two thousand, thirteen".
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