Base | Representation |
---|---|
bin | 10100111000010101… |
… | …11000000000011101 |
3 | 1001221020122120210021 |
4 | 22130022320000131 |
5 | 140424231444013 |
6 | 5052205512141 |
7 | 544536456340 |
oct | 123412700035 |
9 | 31836576707 |
10 | 11210031133 |
11 | 4832852344 |
12 | 220a272651 |
13 | 10985b4722 |
14 | 784b44457 |
15 | 45922aa8d |
hex | 29c2b801d |
11210031133 has 4 divisors (see below), whose sum is σ = 12811464160. Its totient is φ = 9608598108.
The previous prime is 11210031089. The next prime is 11210031163. The reversal of 11210031133 is 33113001211.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11210031133 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11210031163) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 800716503 + ... + 800716516.
It is an arithmetic number, because the mean of its divisors is an integer number (3202866040).
Almost surely, 211210031133 is an apocalyptic number.
It is an amenable number.
11210031133 is a deficient number, since it is larger than the sum of its proper divisors (1601433027).
11210031133 is an equidigital number, since it uses as much as digits as its factorization.
11210031133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1601433026.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 11210031133 its reverse (33113001211), we get a palindrome (44323032344).
The spelling of 11210031133 in words is "eleven billion, two hundred ten million, thirty-one thousand, one hundred thirty-three".
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