11210141253 has 4 divisors (see below), whose sum is σ = 14946855008. Its totient is φ = 7473427500.

The previous prime is 11210141251. The next prime is 11210141311. The reversal of 11210141253 is 35214101211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35214101211 = 3 ⋅11738033737.

It is not a de Polignac number, because 11210141253 - 2¹ = 11210141251 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11210141251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1868356873 + ... + 1868356878.

It is an arithmetic number, because the mean of its divisors is an integer number (3736713752).

Almost surely, 2^11210141253 is an apocalyptic number.

It is an amenable number.

11210141253 is a deficient number, since it is larger than the sum of its proper divisors (3736713755).

11210141253 is an equidigital number, since it uses as much as digits as its factorization.

11210141253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3736713754.

The product of its (nonzero) digits is 240, while the sum is 21.

Adding to 11210141253 its reverse (35214101211), we get a palindrome (46424242464).

The spelling of 11210141253 in words is "eleven billion, two hundred ten million, one hundred forty-one thousand, two hundred fifty-three".