Base | Representation |
---|---|
bin | 10100111000010111… |
… | …00011111100011001 |
3 | 1001221020222201122121 |
4 | 22130023203330121 |
5 | 140424303223342 |
6 | 5052213421241 |
7 | 544541136121 |
oct | 123413437431 |
9 | 31836881577 |
10 | 11210211097 |
11 | 4832965578 |
12 | 220a33a821 |
13 | 1098648607 |
14 | 784b8dc81 |
15 | 459264067 |
hex | 29c2e3f19 |
11210211097 has 4 divisors (see below), whose sum is σ = 11234423680. Its totient is φ = 11185998516.
The previous prime is 11210211091. The next prime is 11210211107. The reversal of 11210211097 is 79011201211.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 79011201211 = 337 ⋅234454603.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11210211097 is a prime.
It is a super-3 number, since 3×112102110973 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11210211091) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12105597 + ... + 12106522.
It is an arithmetic number, because the mean of its divisors is an integer number (2808605920).
Almost surely, 211210211097 is an apocalyptic number.
It is an amenable number.
11210211097 is a deficient number, since it is larger than the sum of its proper divisors (24212583).
11210211097 is an equidigital number, since it uses as much as digits as its factorization.
11210211097 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24212582.
The product of its (nonzero) digits is 252, while the sum is 25.
The spelling of 11210211097 in words is "eleven billion, two hundred ten million, two hundred eleven thousand, ninety-seven".
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