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11210220131 = 111019110921
BaseRepresentation
bin10100111000010111…
…00110001001100011
31001221021000012001012
422130023212021203
5140424304021011
65052213531135
7544541204345
oct123413461143
931837005035
1011210220131
114832971340
12220a343aab
13109864c766
14784b93295
15459266a8b
hex29c2e6263

11210220131 has 4 divisors (see below), whose sum is σ = 12229331064. Its totient is φ = 10191109200.

The previous prime is 11210220113. The next prime is 11210220143. The reversal of 11210220131 is 13102201211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11210220131 - 26 = 11210220067 is a prime.

It is a super-2 number, since 2×112102201312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11210220101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 509555450 + ... + 509555471.

It is an arithmetic number, because the mean of its divisors is an integer number (3057332766).

Almost surely, 211210220131 is an apocalyptic number.

11210220131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

11210220131 is a deficient number, since it is larger than the sum of its proper divisors (1019110933).

11210220131 is a wasteful number, since it uses less digits than its factorization.

11210220131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1019110932.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 11210220131 its reverse (13102201211), we get a palindrome (24312421342).

The spelling of 11210220131 in words is "eleven billion, two hundred ten million, two hundred twenty thousand, one hundred thirty-one".

Divisors: 1 11 1019110921 11210220131