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11210431005 = 325249120689
BaseRepresentation
bin10100111000011000…
…11001101000011101
31001221021101220022100
422130030121220131
5140424332243010
65052222235313
7544543043214
oct123414315035
931837356270
1011210431005
114832aa5814
12220a425b39
1310986c4737
14784c0a07b
154592a92c0
hex29c319a1d

11210431005 has 12 divisors (see below), whose sum is σ = 19431413820. Its totient is φ = 5978896512.

The previous prime is 11210430961. The next prime is 11210431021. The reversal of 11210431005 is 50013401211.

It can be written as a sum of positive squares in 2 ways, for example, as 4461972804 + 6748458201 = 66798^2 + 82149^2 .

It is a de Polignac number, because none of the positive numbers 2k-11210431005 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 124560300 + ... + 124560389.

It is an arithmetic number, because the mean of its divisors is an integer number (1619284485).

Almost surely, 211210431005 is an apocalyptic number.

11210431005 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

11210431005 is a deficient number, since it is larger than the sum of its proper divisors (8220982815).

11210431005 is a wasteful number, since it uses less digits than its factorization.

11210431005 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 249120700 (or 249120697 counting only the distinct ones).

The product of its (nonzero) digits is 120, while the sum is 18.

Adding to 11210431005 its reverse (50013401211), we get a palindrome (61223832216).

The spelling of 11210431005 in words is "eleven billion, two hundred ten million, four hundred thirty-one thousand, five".

Divisors: 1 3 5 9 15 45 249120689 747362067 1245603445 2242086201 3736810335 11210431005