Base | Representation |
---|---|
bin | 110100001101001001… |
… | …0001001000101010111 |
3 | 101201101010221211101112 |
4 | 1220122102021011113 |
5 | 3314100142104421 |
6 | 123300324445235 |
7 | 11046123144503 |
oct | 1503222110527 |
9 | 351333854345 |
10 | 112110113111 |
11 | 43600266347 |
12 | 1988954981b |
13 | a758718c49 |
14 | 55d7543303 |
15 | 2db24ab45b |
hex | 1a1a489157 |
112110113111 has 4 divisors (see below), whose sum is σ = 118010645400. Its totient is φ = 106209580824.
The previous prime is 112110113083. The next prime is 112110113117. The reversal of 112110113111 is 111311011211.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 112110113111 - 214 = 112110096727 is a prime.
It is a super-2 number, since 2×1121101131112 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112110113117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2950266116 + ... + 2950266153.
It is an arithmetic number, because the mean of its divisors is an integer number (29502661350).
Almost surely, 2112110113111 is an apocalyptic number.
112110113111 is a deficient number, since it is larger than the sum of its proper divisors (5900532289).
112110113111 is an equidigital number, since it uses as much as digits as its factorization.
112110113111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5900532288.
The product of its (nonzero) digits is 6, while the sum is 14.
Adding to 112110113111 its reverse (111311011211), we get a palindrome (223421124322).
The spelling of 112110113111 in words is "one hundred twelve billion, one hundred ten million, one hundred thirteen thousand, one hundred eleven".
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