Base | Representation |
---|---|
bin | 1010001100100100011011… |
… | …0111001001110000010011 |
3 | 1110200202200121001121212110 |
4 | 2203021012313021300103 |
5 | 2432140214144134210 |
6 | 35502141544400403 |
7 | 2234654233321131 |
oct | 243110667116023 |
9 | 43622617047773 |
10 | 11211053505555 |
11 | 3632643483472 |
12 | 131093b176103 |
13 | 634275782757 |
14 | 2aa891694751 |
15 | 14695a23b420 |
hex | a3246dc9c13 |
11211053505555 has 8 divisors (see below), whose sum is σ = 17937685608912. Its totient is φ = 5979228536288.
The previous prime is 11211053505469. The next prime is 11211053505577. The reversal of 11211053505555 is 55550535011211.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11211053505555 - 214 = 11211053489171 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 373701783504 + ... + 373701783533.
It is an arithmetic number, because the mean of its divisors is an integer number (2242210701114).
Almost surely, 211211053505555 is an apocalyptic number.
11211053505555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11211053505555 is a deficient number, since it is larger than the sum of its proper divisors (6726632103357).
11211053505555 is an equidigital number, since it uses as much as digits as its factorization.
11211053505555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 747403567045.
The product of its (nonzero) digits is 93750, while the sum is 39.
Adding to 11211053505555 its reverse (55550535011211), we get a palindrome (66761588516766).
The spelling of 11211053505555 in words is "eleven trillion, two hundred eleven billion, fifty-three million, five hundred five thousand, five hundred fifty-five".
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