Base | Representation |
---|---|
bin | 10000010100001000000… |
… | …010010111111000101111 |
3 | 10222011210212112012001101 |
4 | 100110020002113320233 |
5 | 121332024023212421 |
6 | 2215011440223531 |
7 | 143666300564434 |
oct | 20241002277057 |
9 | 3864725465041 |
10 | 1121121304111 |
11 | 3a2512826426 |
12 | 16134530aba7 |
13 | 8194b882763 |
14 | 3c396675b8b |
15 | 1e269db0191 |
hex | 10508097e2f |
1121121304111 has 4 divisors (see below), whose sum is σ = 1127384551800. Its totient is φ = 1114858056424.
The previous prime is 1121121304103. The next prime is 1121121304117. The reversal of 1121121304111 is 1114031211211.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1121121304111 - 23 = 1121121304103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1121121304117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3131623576 + ... + 3131623933.
It is an arithmetic number, because the mean of its divisors is an integer number (281846137950).
Almost surely, 21121121304111 is an apocalyptic number.
1121121304111 is a deficient number, since it is larger than the sum of its proper divisors (6263247689).
1121121304111 is an equidigital number, since it uses as much as digits as its factorization.
1121121304111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6263247688.
The product of its (nonzero) digits is 48, while the sum is 19.
Adding to 1121121304111 its reverse (1114031211211), we get a palindrome (2235152515322).
The spelling of 1121121304111 in words is "one trillion, one hundred twenty-one billion, one hundred twenty-one million, three hundred four thousand, one hundred eleven".
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