Base | Representation |
---|---|
bin | 10100111000011111… |
… | …10101000111010010 |
3 | 1001221100002120111112 |
4 | 22130033311013102 |
5 | 140430100030002 |
6 | 5052253413322 |
7 | 544553506205 |
oct | 123417650722 |
9 | 31840076445 |
10 | 11211330002 |
11 | 483355a194 |
12 | 220a79a242 |
13 | 109894a9a2 |
14 | 784da193c |
15 | 4593d5852 |
hex | 29c3f51d2 |
11211330002 has 4 divisors (see below), whose sum is σ = 16816995006. Its totient is φ = 5605665000.
The previous prime is 11211329989. The next prime is 11211330007. The reversal of 11211330002 is 20003311211.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 10709973121 + 501356881 = 103489^2 + 22391^2 .
It is not an unprimeable number, because it can be changed into a prime (11211330007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2802832499 + ... + 2802832502.
Almost surely, 211211330002 is an apocalyptic number.
11211330002 is a deficient number, since it is larger than the sum of its proper divisors (5605665004).
11211330002 is an equidigital number, since it uses as much as digits as its factorization.
11211330002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5605665003.
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 11211330002 its reverse (20003311211), we get a palindrome (31214641213).
The spelling of 11211330002 in words is "eleven billion, two hundred eleven million, three hundred thirty thousand, two".
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