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11211333013 = 90111244183
BaseRepresentation
bin10100111000011111…
…10101110110010101
31001221100002201122001
422130033311312111
5140430100124023
65052253435301
7544553521036
oct123417656625
931840081561
1011211333013
114833561481
12220a79bb31
13109894c17a
14784da2a8d
154593d66ad
hex29c3f5d95

11211333013 has 4 divisors (see below), whose sum is σ = 11212586208. Its totient is φ = 11210079820.

The previous prime is 11211333011. The next prime is 11211333017. The reversal of 11211333013 is 31033311211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11211333013 - 21 = 11211333011 is a prime.

It is a super-3 number, since 3×112113330133 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11211333011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 613081 + ... + 631102.

It is an arithmetic number, because the mean of its divisors is an integer number (2803146552).

Almost surely, 211211333013 is an apocalyptic number.

It is an amenable number.

11211333013 is a deficient number, since it is larger than the sum of its proper divisors (1253195).

11211333013 is an equidigital number, since it uses as much as digits as its factorization.

11211333013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1253194.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 11211333013 its reverse (31033311211), we get a palindrome (42244644224).

The spelling of 11211333013 in words is "eleven billion, two hundred eleven million, three hundred thirty-three thousand, thirteen".

Divisors: 1 9011 1244183 11211333013