112120234002333 has 12 divisors (see below), whose sum is σ = 162013906321020. Its totient is φ = 74717996265216.

The previous prime is 112120234002319. The next prime is 112120234002391. The reversal of 112120234002333 is 333200432021211.

112120234002333 is a `hidden beast` number, since 1 + 1 + 2 + 1 + 2 + 0 + 23 + 400 + 233 + 3 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 54428583370329 + 57691650632004 = 7377573^2 + 7595502^2 .

It is not a de Polignac number, because 112120234002333 - 2⁹ = 112120234001821 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 112120234002297 and 112120234002306.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (112120234004333) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2402175618 + ... + 2402222291.

It is an arithmetic number, because the mean of its divisors is an integer number (13501158860085).

Almost surely, 2^{112120234002333} is an apocalyptic number.

It is an amenable number.

112120234002333 is a deficient number, since it is larger than the sum of its proper divisors (49893672318687).

112120234002333 is a wasteful number, since it uses less digits than its factorization.

112120234002333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4804400508 (or 4804400505 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 27.

Adding to 112120234002333 its reverse (333200432021211), we get a palindrome (445320666023544).

The spelling of 112120234002333 in words is "one hundred twelve trillion, one hundred twenty billion, two hundred thirty-four million, two thousand, three hundred thirty-three".