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11212032013 = 713149826907
BaseRepresentation
bin10100111000100101…
…00000100000001101
31001221101102020110221
422130102200200031
5140430240011023
65052320431341
7544562461660
oct123422404015
931841366427
1011212032013
114833999666
12220aa78551
131098b35390
147851056d7
154594c385d
hex29c4a080d

11212032013 has 16 divisors (see below), whose sum is σ = 13892054400. Its totient is φ = 8811510336.

The previous prime is 11212031977. The next prime is 11212032037. The reversal of 11212032013 is 31023021211.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11212032013 is a prime.

It is a super-3 number, since 3×112120320133 (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11212032413) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 399895 + ... + 427012.

It is an arithmetic number, because the mean of its divisors is an integer number (868253400).

Almost surely, 211212032013 is an apocalyptic number.

11212032013 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11212032013 is a deficient number, since it is larger than the sum of its proper divisors (2680022387).

11212032013 is a wasteful number, since it uses less digits than its factorization.

11212032013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 827076.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 11212032013 its reverse (31023021211), we get a palindrome (42235053224).

The spelling of 11212032013 in words is "eleven billion, two hundred twelve million, thirty-two thousand, thirteen".

Divisors: 1 7 13 91 149 1043 1937 13559 826907 5788349 10749791 75248537 123209143 862464001 1601718859 11212032013