Base | Representation |
---|---|
bin | 11001011111100100111010… |
… | …010101101000100111100010 |
3 | 112200222200011020102122100212 |
4 | 121133210322111220213202 |
5 | 104143443003100341002 |
6 | 1034243420002214122 |
7 | 32421324244243244 |
oct | 3137447225504742 |
9 | 480880136378325 |
10 | 112121100012002 |
11 | 327a8322a69424 |
12 | 106a99a1654342 |
13 | 4a73c888a6163 |
14 | 1d98993c7a094 |
15 | ce67d9030352 |
hex | 65f93a5689e2 |
112121100012002 has 4 divisors (see below), whose sum is σ = 168181650018006. Its totient is φ = 56060550006000.
The previous prime is 112121100011911. The next prime is 112121100012043. The reversal of 112121100012002 is 200210001121211.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 82220118435961 + 29900981576041 = 9067531^2 + 5468179^2 .
It is a super-2 number, since 2×1121211000120022 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28030275002999 + ... + 28030275003002.
Almost surely, 2112121100012002 is an apocalyptic number.
112121100012002 is a deficient number, since it is larger than the sum of its proper divisors (56060550006004).
112121100012002 is an equidigital number, since it uses as much as digits as its factorization.
112121100012002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 56060550006003.
The product of its (nonzero) digits is 16, while the sum is 14.
Adding to 112121100012002 its reverse (200210001121211), we get a palindrome (312331101133213).
The spelling of 112121100012002 in words is "one hundred twelve trillion, one hundred twenty-one billion, one hundred million, twelve thousand, two".
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