Base | Representation |
---|---|
bin | 11001011111100100111010… |
… | …100001011111011010011111 |
3 | 112200222200011110021112210001 |
4 | 121133210322201133122133 |
5 | 104143443004344320111 |
6 | 1034243420152555131 |
7 | 32421324312536455 |
oct | 3137447241373237 |
9 | 480880143245701 |
10 | 112121103120031 |
11 | 327a83247a1545 |
12 | 106a99a26b2aa7 |
13 | 4a73c89423a25 |
14 | 1d989944489d5 |
15 | ce67d94461c1 |
hex | 65f93a85f69f |
112121103120031 has 4 divisors (see below), whose sum is σ = 112121148469000. Its totient is φ = 112121057771064.
The previous prime is 112121103120023. The next prime is 112121103120043. The reversal of 112121103120031 is 130021301121211.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 112121103120031 - 23 = 112121103120023 is a prime.
It is a super-2 number, since 2×1121211031200312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 112121103119990 and 112121103120008.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112121103120731) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18738081 + ... + 23986618.
It is an arithmetic number, because the mean of its divisors is an integer number (28030287117250).
Almost surely, 2112121103120031 is an apocalyptic number.
112121103120031 is a deficient number, since it is larger than the sum of its proper divisors (45348969).
112121103120031 is an equidigital number, since it uses as much as digits as its factorization.
112121103120031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 45348968.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 112121103120031 its reverse (130021301121211), we get a palindrome (242142404241242).
The spelling of 112121103120031 in words is "one hundred twelve trillion, one hundred twenty-one billion, one hundred three million, one hundred twenty thousand, thirty-one".
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