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1121211033002 = 2560605516501
BaseRepresentation
bin10000010100001101011…
…000101010010110101010
310222012001010100212221122
4100110031120222112222
5121332220011024002
62215024403335242
7144001440350624
oct20241530522652
93865033325848
101121211033002
113a2559442035
1216136b381522
138196433b188
143c3a4551c14
151e272bd66a2
hex1050d62a5aa

1121211033002 has 4 divisors (see below), whose sum is σ = 1681816549506. Its totient is φ = 560605516500.

The previous prime is 1121211032983. The next prime is 1121211033011. The reversal of 1121211033002 is 2003301121211.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1114669296841 + 6541736161 = 1055779^2 + 80881^2 .

It is a super-2 number, since 2×11212110330022 (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 280302758249 + ... + 280302758252.

Almost surely, 21121211033002 is an apocalyptic number.

1121211033002 is a deficient number, since it is larger than the sum of its proper divisors (560605516504).

1121211033002 is an equidigital number, since it uses as much as digits as its factorization.

1121211033002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 560605516503.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1121211033002 its reverse (2003301121211), we get a palindrome (3124512154213).

The spelling of 1121211033002 in words is "one trillion, one hundred twenty-one billion, two hundred eleven million, thirty-three thousand, two".

Divisors: 1 2 560605516501 1121211033002