Base | Representation |
---|---|
bin | 110100001101011110… |
… | …0011100101001100111 |
3 | 101201101220211021021101 |
4 | 1220122330130221213 |
5 | 3314111012001203 |
6 | 123301402300531 |
7 | 11046316334434 |
oct | 1503274345147 |
9 | 351356737241 |
10 | 112121203303 |
11 | 4360655059a |
12 | 198911b7747 |
13 | a75aaccaa5 |
14 | 55d8bccb8b |
15 | 2db344c41d |
hex | 1a1af1ca67 |
112121203303 has 4 divisors (see below), whose sum is σ = 112122657720. Its totient is φ = 112119748888.
The previous prime is 112121203277. The next prime is 112121203307. The reversal of 112121203303 is 303302121211.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112121203303 is a prime.
It is a super-2 number, since 2×1121212033032 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112121203307) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 604693 + ... + 768046.
It is an arithmetic number, because the mean of its divisors is an integer number (28030664430).
Almost surely, 2112121203303 is an apocalyptic number.
112121203303 is a deficient number, since it is larger than the sum of its proper divisors (1454417).
112121203303 is an equidigital number, since it uses as much as digits as its factorization.
112121203303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1454416.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 112121203303 its reverse (303302121211), we get a palindrome (415423324514).
The spelling of 112121203303 in words is "one hundred twelve billion, one hundred twenty-one million, two hundred three thousand, three hundred three".
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