Base | Representation |
---|---|
bin | 1010001100101000011001… |
… | …1111011001101101110111 |
3 | 1110200212102222210001011202 |
4 | 2203022012133121231313 |
5 | 2432144410440140203 |
6 | 35502435521123115 |
7 | 2235022545131006 |
oct | 243120637315567 |
9 | 43625388701152 |
10 | 11212121021303 |
11 | 3633041020894 |
12 | 1310b9878949b |
13 | 6343b599b787 |
14 | 2aa953378c3d |
15 | 1469bdd07388 |
hex | a32867d9b77 |
11212121021303 has 4 divisors (see below), whose sum is σ = 11217652410120. Its totient is φ = 11206589632488.
The previous prime is 11212121021263. The next prime is 11212121021347. The reversal of 11212121021303 is 30312012121211.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11212121021303 - 224 = 11212104244087 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11212121021363) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2765691368 + ... + 2765695421.
It is an arithmetic number, because the mean of its divisors is an integer number (2804413102530).
Almost surely, 211212121021303 is an apocalyptic number.
11212121021303 is a deficient number, since it is larger than the sum of its proper divisors (5531388817).
11212121021303 is an equidigital number, since it uses as much as digits as its factorization.
11212121021303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5531388816.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 11212121021303 its reverse (30312012121211), we get a palindrome (41524133142514).
The spelling of 11212121021303 in words is "eleven trillion, two hundred twelve billion, one hundred twenty-one million, twenty-one thousand, three hundred three".
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