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1121213002023 = 32124579222447
BaseRepresentation
bin10000010100001101100…
…000001011000100100111
310222012001021001220221100
4100110031200023010213
5121332221012031043
62215024513451143
7144001463161332
oct20241540130447
93865037056840
101121213002023
113a255a567424
1216136bb70ab3
138196487a48a
143c3a4905619
151e272e74cd3
hex1050d80b127

1121213002023 has 6 divisors (see below), whose sum is σ = 1619529891824. Its totient is φ = 747475334676.

The previous prime is 1121213001991. The next prime is 1121213002043. The reversal of 1121213002023 is 3202003121211.

It is not a de Polignac number, because 1121213002023 - 25 = 1121213001991 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1121213001987 and 1121213002005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1121213002043) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 62289611215 + ... + 62289611232.

Almost surely, 21121213002023 is an apocalyptic number.

1121213002023 is a deficient number, since it is larger than the sum of its proper divisors (498316889801).

1121213002023 is a wasteful number, since it uses less digits than its factorization.

1121213002023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 124579222453 (or 124579222450 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 1121213002023 its reverse (3202003121211), we get a palindrome (4323216123234).

The spelling of 1121213002023 in words is "one trillion, one hundred twenty-one billion, two hundred thirteen million, two thousand, twenty-three".

Divisors: 1 3 9 124579222447 373737667341 1121213002023