Base | Representation |
---|---|
bin | 1010001100101001001100… |
… | …1001001110100011101010 |
3 | 1110200212222210020112120211 |
4 | 2203022103021032203222 |
5 | 2432200324311442414 |
6 | 35502512543211334 |
7 | 2235031033436005 |
oct | 243122311164352 |
9 | 43625883215524 |
10 | 11212333312234 |
11 | 363313a93913a |
12 | 13110378a6b4a |
13 | 63441a96a302 |
14 | 2aa97363a53c |
15 | 1469d278d3c4 |
hex | a329324e8ea |
11212333312234 has 4 divisors (see below), whose sum is σ = 16818499968354. Its totient is φ = 5606166656116.
The previous prime is 11212333312189. The next prime is 11212333312267. The reversal of 11212333312234 is 43221333321211.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 8251342425225 + 2960990887009 = 2872515^2 + 1720753^2 .
It is a super-2 number, since 2×112123333122342 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11212333312196 and 11212333312205.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2803083328057 + ... + 2803083328060.
Almost surely, 211212333312234 is an apocalyptic number.
11212333312234 is a deficient number, since it is larger than the sum of its proper divisors (5606166656120).
11212333312234 is an equidigital number, since it uses as much as digits as its factorization.
11212333312234 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5606166656119.
The product of its digits is 15552, while the sum is 31.
Adding to 11212333312234 its reverse (43221333321211), we get a palindrome (54433666633445).
The spelling of 11212333312234 in words is "eleven trillion, two hundred twelve billion, three hundred thirty-three million, three hundred twelve thousand, two hundred thirty-four".
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