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11212404133 = 71601772019
BaseRepresentation
bin10100111000100111…
…11011010110100101
31001221102010010221011
422130103323112211
5140430333413013
65052332422221
7544565601610
oct123423732645
931842103834
1011212404133
1148341231a7
12220b017971
131098c35878
147851a1177
15459548c3d
hex29c4fb5a5

11212404133 has 4 divisors (see below), whose sum is σ = 12814176160. Its totient is φ = 9610632108.

The previous prime is 11212404131. The next prime is 11212404143. The reversal of 11212404133 is 33140421211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 11212404133 - 21 = 11212404131 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11212404131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 800886003 + ... + 800886016.

It is an arithmetic number, because the mean of its divisors is an integer number (3203544040).

Almost surely, 211212404133 is an apocalyptic number.

It is an amenable number.

11212404133 is a deficient number, since it is larger than the sum of its proper divisors (1601772027).

11212404133 is an equidigital number, since it uses as much as digits as its factorization.

11212404133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1601772026.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 11212404133 its reverse (33140421211), we get a palindrome (44352825344).

The spelling of 11212404133 in words is "eleven billion, two hundred twelve million, four hundred four thousand, one hundred thirty-three".

Divisors: 1 7 1601772019 11212404133