Base | Representation |
---|---|
bin | 11001011111101000110111… |
… | …010001010101100110111011 |
3 | 112201000002002222100020122121 |
4 | 121133220313101111212323 |
5 | 104144030200420134321 |
6 | 1034245401031302111 |
7 | 32421534352416226 |
oct | 3137506721254673 |
9 | 481002088306577 |
10 | 112125343521211 |
11 | 327aa100352729 |
12 | 106aa78681a937 |
13 | 4a744b3aa6a57 |
14 | 1d98c7769a5bd |
15 | ce6986856441 |
hex | 65fa374559bb |
112125343521211 has 4 divisors (see below), whose sum is σ = 112128982921800. Its totient is φ = 112121704120624.
The previous prime is 112125343521197. The next prime is 112125343521221.
112125343521211 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 112125343521211 - 219 = 112125342996923 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (112125343521221) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1819654081 + ... + 1819715698.
It is an arithmetic number, because the mean of its divisors is an integer number (28032245730450).
Almost surely, 2112125343521211 is an apocalyptic number.
112125343521211 is a deficient number, since it is larger than the sum of its proper divisors (3639400589).
112125343521211 is an equidigital number, since it uses as much as digits as its factorization.
112125343521211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3639400588.
The product of its digits is 14400, while the sum is 34.
The spelling of 112125343521211 in words is "one hundred twelve trillion, one hundred twenty-five billion, three hundred forty-three million, five hundred twenty-one thousand, two hundred eleven".
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