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11213001215 = 513172507711
BaseRepresentation
bin10100111000101100…
…01101000111111111
31001221110020110222022
422130112031013333
5140431012014330
65052353310355
7544603636433
oct123426150777
931843213868
1011213001215
1148344a0859
12220b2653bb
1310990b4580
147852b89c3
15459615ae5
hex29c58d1ff

11213001215 has 8 divisors (see below), whose sum is σ = 14490647808. Its totient is φ = 8280370080.

The previous prime is 11213001203. The next prime is 11213001257. The reversal of 11213001215 is 51210031211.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11213001215 - 218 = 11212739071 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11213001193 and 11213001202.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 86253791 + ... + 86253920.

It is an arithmetic number, because the mean of its divisors is an integer number (1811330976).

Almost surely, 211213001215 is an apocalyptic number.

11213001215 is a deficient number, since it is larger than the sum of its proper divisors (3277646593).

11213001215 is a wasteful number, since it uses less digits than its factorization.

11213001215 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 172507729.

The product of its (nonzero) digits is 60, while the sum is 17.

Adding to 11213001215 its reverse (51210031211), we get a palindrome (62423032426).

The spelling of 11213001215 in words is "eleven billion, two hundred thirteen million, one thousand, two hundred fifteen".

Divisors: 1 5 13 65 172507711 862538555 2242600243 11213001215