Base | Representation |
---|---|
bin | 10100111000101100… |
… | …01101100111100011 |
3 | 1001221110020120202010 |
4 | 22130112031213203 |
5 | 140431012100420 |
6 | 5052353324003 |
7 | 544603645350 |
oct | 123426154743 |
9 | 31843216663 |
10 | 11213003235 |
11 | 48344a2325 |
12 | 220b266603 |
13 | 10990b5475 |
14 | 7852b9627 |
15 | 4596164e0 |
hex | 29c58d9e3 |
11213003235 has 64 divisors (see below), whose sum is σ = 21607787520. Its totient is φ = 4850565120.
The previous prime is 11213003183. The next prime is 11213003237. The reversal of 11213003235 is 53230031211.
It is not a de Polignac number, because 11213003235 - 27 = 11213003107 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is not an unprimeable number, because it can be changed into a prime (11213003237) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2058115 + ... + 2063555.
It is an arithmetic number, because the mean of its divisors is an integer number (337621680).
Almost surely, 211213003235 is an apocalyptic number.
11213003235 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11213003235 is a deficient number, since it is larger than the sum of its proper divisors (10394784285).
11213003235 is a wasteful number, since it uses less digits than its factorization.
11213003235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6508.
The product of its (nonzero) digits is 540, while the sum is 21.
Adding to 11213003235 its reverse (53230031211), we get a palindrome (64443034446).
The spelling of 11213003235 in words is "eleven billion, two hundred thirteen million, three thousand, two hundred thirty-five".
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