Base | Representation |
---|---|
bin | 110100001101101111… |
… | …0011000101110000111 |
3 | 101201102112120021101111 |
4 | 1220123132120232013 |
5 | 3314120301200403 |
6 | 123302321105451 |
7 | 11046455060560 |
oct | 1503336305607 |
9 | 351375507344 |
10 | 112130100103 |
11 | 4361057791a |
12 | 19894188287 |
13 | a75c8c6478 |
14 | 55da067167 |
15 | 2db410856d |
hex | 1a1b798b87 |
112130100103 has 8 divisors (see below), whose sum is σ = 128723345408. Its totient is φ = 95680519704.
The previous prime is 112130100083. The next prime is 112130100221. The reversal of 112130100103 is 301001031211.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 112130100103 - 217 = 112129969031 is a prime.
It is a super-2 number, since 2×1121301001032 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112130104103) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35914551 + ... + 35917672.
It is an arithmetic number, because the mean of its divisors is an integer number (16090418176).
Almost surely, 2112130100103 is an apocalyptic number.
112130100103 is a deficient number, since it is larger than the sum of its proper divisors (16593245305).
112130100103 is an equidigital number, since it uses as much as digits as its factorization.
112130100103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71832453.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 112130100103 its reverse (301001031211), we get a palindrome (413131131314).
The spelling of 112130100103 in words is "one hundred twelve billion, one hundred thirty million, one hundred thousand, one hundred three".
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