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11213100113 = 313149923899
BaseRepresentation
bin10100111000101101…
…00101010001010001
31001221110102111122012
422130112211101101
5140431023200423
65052355352305
7544604530655
oct123426452121
931843374565
1011213100113
114834559096
12220b2b2695
13109911a5a7
14785302a65
15459635078
hex29c5a5451

11213100113 has 8 divisors (see below), whose sum is σ = 11256900000. Its totient is φ = 11169351648.

The previous prime is 11213100089. The next prime is 11213100133. The reversal of 11213100113 is 31100131211.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11213100113 is a prime.

It is a super-2 number, since 2×112131001132 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11213100133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 457238 + ... + 481136.

It is an arithmetic number, because the mean of its divisors is an integer number (1407112500).

Almost surely, 211213100113 is an apocalyptic number.

It is an amenable number.

11213100113 is a deficient number, since it is larger than the sum of its proper divisors (43799887).

11213100113 is a wasteful number, since it uses less digits than its factorization.

11213100113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25711.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 11213100113 its reverse (31100131211), we get a palindrome (42313231324).

The spelling of 11213100113 in words is "eleven billion, two hundred thirteen million, one hundred thousand, one hundred thirteen".

Divisors: 1 313 1499 23899 469187 7480387 35824601 11213100113