Base | Representation |
---|---|
bin | 11001011111101110001001… |
… | …000110101110111110101011 |
3 | 112201000121201222112101022021 |
4 | 121133232021012232332223 |
5 | 104144123302412044210 |
6 | 1034252135302405311 |
7 | 32422124665062352 |
oct | 3137561106567653 |
9 | 481017658471267 |
10 | 112131011440555 |
11 | 32801549788398 |
12 | 106ab8a8a30837 |
13 | 4a74ba8121993 |
14 | 1d99254344999 |
15 | ce6bb9244bda |
hex | 65fb891aefab |
112131011440555 has 16 divisors (see below), whose sum is σ = 135198920728224. Its totient is φ = 89277029614080.
The previous prime is 112131011440529. The next prime is 112131011440573. The reversal of 112131011440555 is 555044110131211.
It is not a de Polignac number, because 112131011440555 - 25 = 112131011440523 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 112131011440555.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 34541427 + ... + 37648003.
It is an arithmetic number, because the mean of its divisors is an integer number (8449932545514).
Almost surely, 2112131011440555 is an apocalyptic number.
112131011440555 is a deficient number, since it is larger than the sum of its proper divisors (23067909287669).
112131011440555 is a wasteful number, since it uses less digits than its factorization.
112131011440555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3141006.
The product of its (nonzero) digits is 12000, while the sum is 34.
Adding to 112131011440555 its reverse (555044110131211), we get a palindrome (667175121571766).
The spelling of 112131011440555 in words is "one hundred twelve trillion, one hundred thirty-one billion, eleven million, four hundred forty thousand, five hundred fifty-five".
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