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1121310220322 = 2560655110161
BaseRepresentation
bin10000010100010011010…
…011000010000000100010
310222012022001000010101002
4100110103103002000202
5121332420404022242
62215042305312002
7144004053416525
oct20242323020042
93865261003332
101121310220322
113a25aa428a26
12161398635602
138197ba58ab6
143c3b37b0bbc
151e27b77a432
hex105134c2022

1121310220322 has 4 divisors (see below), whose sum is σ = 1681965330486. Its totient is φ = 560655110160.

The previous prime is 1121310220253. The next prime is 1121310220337. The reversal of 1121310220322 is 2230220131211.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1051361078881 + 69949141441 = 1025359^2 + 264479^2 .

It is a super-2 number, since 2×11213102203222 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1121310220294 and 1121310220303.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 280327555079 + ... + 280327555082.

Almost surely, 21121310220322 is an apocalyptic number.

1121310220322 is a deficient number, since it is larger than the sum of its proper divisors (560655110164).

1121310220322 is an equidigital number, since it uses as much as digits as its factorization.

1121310220322 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 560655110163.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 1121310220322 its reverse (2230220131211), we get a palindrome (3351530351533).

The spelling of 1121310220322 in words is "one trillion, one hundred twenty-one billion, three hundred ten million, two hundred twenty thousand, three hundred twenty-two".

Divisors: 1 2 560655110161 1121310220322