11213111303 has 4 divisors (see below), whose sum is σ = 11213583360. Its totient is φ = 11212639248.

The previous prime is 11213111297. The next prime is 11213111309. The reversal of 11213111303 is 30311131211.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (11213111297) and next prime (11213111309).

It is a cyclic number.

It is not a de Polignac number, because 11213111303 - 2¹² = 11213107207 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11213111309) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 198398 + ... + 248571.

It is an arithmetic number, because the mean of its divisors is an integer number (2803395840).

Almost surely, 2^11213111303 is an apocalyptic number.

11213111303 is a deficient number, since it is larger than the sum of its proper divisors (472057).

11213111303 is an equidigital number, since it uses as much as digits as its factorization.

11213111303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 472056.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11213111303 its reverse (30311131211), we get a palindrome (41524242514).

The spelling of 11213111303 in words is "eleven billion, two hundred thirteen million, one hundred eleven thousand, three hundred three".