Base | Representation |
---|---|
bin | 10100111000101101… |
… | …01101101001101001 |
3 | 1001221110111020201121 |
4 | 22130112231221221 |
5 | 140431030300231 |
6 | 5052400215241 |
7 | 544605033025 |
oct | 123426555151 |
9 | 31843436647 |
10 | 11213134441 |
11 | 4834581963 |
12 | 220b30a521 |
13 | 10991300c2 |
14 | 785311385 |
15 | 459640311 |
hex | 29c5ada69 |
11213134441 has 4 divisors (see below), whose sum is σ = 11371065984. Its totient is φ = 11055202900.
The previous prime is 11213134423. The next prime is 11213134447. The reversal of 11213134441 is 14443131211.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11213134441 - 217 = 11213003369 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11213134447) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 78965665 + ... + 78965806.
It is an arithmetic number, because the mean of its divisors is an integer number (2842766496).
Almost surely, 211213134441 is an apocalyptic number.
It is an amenable number.
11213134441 is a deficient number, since it is larger than the sum of its proper divisors (157931543).
11213134441 is an equidigital number, since it uses as much as digits as its factorization.
11213134441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 157931542.
The product of its digits is 1152, while the sum is 25.
Adding to 11213134441 its reverse (14443131211), we get a palindrome (25656265652).
The spelling of 11213134441 in words is "eleven billion, two hundred thirteen million, one hundred thirty-four thousand, four hundred forty-one".
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