Base | Representation |
---|---|
bin | 1010001100101100100110… |
… | …0100000001010011010101 |
3 | 1110200222100102012101212222 |
4 | 2203023021210001103111 |
5 | 2432204212023233433 |
6 | 35503143315552125 |
7 | 2235062460651641 |
oct | 243131144012325 |
9 | 43628312171788 |
10 | 11213246305493 |
11 | 3633569235521 |
12 | 13112515bb645 |
13 | 634534b62acb |
14 | 2aaa1c9b9c21 |
15 | 146a379d4b98 |
hex | a32c99014d5 |
11213246305493 has 4 divisors (see below), whose sum is σ = 11403301327680. Its totient is φ = 11023191283308.
The previous prime is 11213246305447. The next prime is 11213246305531. The reversal of 11213246305493 is 39450364231211.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11213246305493 - 234 = 11196066436309 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11213246305193) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95027511005 + ... + 95027511122.
It is an arithmetic number, because the mean of its divisors is an integer number (2850825331920).
Almost surely, 211213246305493 is an apocalyptic number.
It is an amenable number.
11213246305493 is a deficient number, since it is larger than the sum of its proper divisors (190055022187).
11213246305493 is an equidigital number, since it uses as much as digits as its factorization.
11213246305493 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 190055022186.
The product of its (nonzero) digits is 466560, while the sum is 44.
The spelling of 11213246305493 in words is "eleven trillion, two hundred thirteen billion, two hundred forty-six million, three hundred five thousand, four hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •