Base | Representation |
---|---|
bin | 1010001100101100110011… |
… | …1100110000000011111010 |
3 | 1110200222111101002212220111 |
4 | 2203023030330300003322 |
5 | 2432204321044320442 |
6 | 35503153105414534 |
7 | 2235064050611155 |
oct | 243131474600372 |
9 | 43628441085814 |
10 | 11213303120122 |
11 | 3633598310164 |
12 | 131126863a44a |
13 | 634543865c2c |
14 | 2aaa26368c9c |
15 | 146a3c9a8b17 |
hex | a32ccf300fa |
11213303120122 has 4 divisors (see below), whose sum is σ = 16819954680186. Its totient is φ = 5606651560060.
The previous prime is 11213303120087. The next prime is 11213303120153. The reversal of 11213303120122 is 22102130331211.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 8995434579121 + 2217868541001 = 2999239^2 + 1489251^2 .
It is a super-2 number, since 2×112133031201222 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11213303120093 and 11213303120102.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2803325780029 + ... + 2803325780032.
Almost surely, 211213303120122 is an apocalyptic number.
11213303120122 is a deficient number, since it is larger than the sum of its proper divisors (5606651560064).
11213303120122 is an equidigital number, since it uses as much as digits as its factorization.
11213303120122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5606651560063.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 11213303120122 its reverse (22102130331211), we get a palindrome (33315433451333).
The spelling of 11213303120122 in words is "eleven trillion, two hundred thirteen billion, three hundred three million, one hundred twenty thousand, one hundred twenty-two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •