Base | Representation |
---|---|
bin | 110100001101110101… |
… | …0011000001000101010 |
3 | 101201102202110222020011 |
4 | 1220123222120020222 |
5 | 3314122102242214 |
6 | 123302512322134 |
7 | 11046523562032 |
oct | 1503352301052 |
9 | 351382428204 |
10 | 112133243434 |
11 | 43612324513 |
12 | 1989524334a |
13 | a760457124 |
14 | 55da6448c2 |
15 | 2db4529ac4 |
hex | 1a1ba9822a |
112133243434 has 4 divisors (see below), whose sum is σ = 168199865154. Its totient is φ = 56066621716.
The previous prime is 112133243423. The next prime is 112133243449. The reversal of 112133243434 is 434342331211.
112133243434 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 94373683209 + 17759560225 = 307203^2 + 133265^2 .
It is a super-2 number, since 2×1121332434342 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 112133243396 and 112133243405.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28033310857 + ... + 28033310860.
Almost surely, 2112133243434 is an apocalyptic number.
112133243434 is a deficient number, since it is larger than the sum of its proper divisors (56066621720).
112133243434 is an equidigital number, since it uses as much as digits as its factorization.
112133243434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56066621719.
The product of its digits is 20736, while the sum is 31.
Adding to 112133243434 its reverse (434342331211), we get a palindrome (546475574645).
The spelling of 112133243434 in words is "one hundred twelve billion, one hundred thirty-three million, two hundred forty-three thousand, four hundred thirty-four".
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