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11213331103 = 13862563931
BaseRepresentation
bin10100111000101110…
…11101101010011111
31001221110212020111101
422130113131222133
5140431103043403
65052404333531
7544606512262
oct123427355237
931843766441
1011213331103
1148346a6697
12220b3a42a7
13109919b780
14785362cd9
1545967d71d
hex29c5dda9f

11213331103 has 4 divisors (see below), whose sum is σ = 12075895048. Its totient is φ = 10350767160.

The previous prime is 11213331089. The next prime is 11213331119. The reversal of 11213331103 is 30113331211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11213331103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11213334103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 431281953 + ... + 431281978.

It is an arithmetic number, because the mean of its divisors is an integer number (3018973762).

Almost surely, 211213331103 is an apocalyptic number.

11213331103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

11213331103 is a deficient number, since it is larger than the sum of its proper divisors (862563945).

11213331103 is an equidigital number, since it uses as much as digits as its factorization.

11213331103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 862563944.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 11213331103 its reverse (30113331211), we get a palindrome (41326662314).

The spelling of 11213331103 in words is "eleven billion, two hundred thirteen million, three hundred thirty-one thousand, one hundred three".

Divisors: 1 13 862563931 11213331103