11213333214133 has 4 divisors (see below), whose sum is σ = 11222239754880. Its totient is φ = 11204426673388.

The previous prime is 11213333214107. The next prime is 11213333214143. The reversal of 11213333214133 is 33141233331211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11213333214133 - 2⁵ = 11213333214101 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11213333214095 and 11213333214104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11213333214103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4453268485 + ... + 4453271002.

It is an arithmetic number, because the mean of its divisors is an integer number (2805559938720).

Almost surely, 2^{11213333214133} is an apocalyptic number.

It is an amenable number.

11213333214133 is a deficient number, since it is larger than the sum of its proper divisors (8906540747).

11213333214133 is an equidigital number, since it uses as much as digits as its factorization.

11213333214133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8906540746.

The product of its digits is 11664, while the sum is 31.

Adding to 11213333214133 its reverse (33141233331211), we get a palindrome (44354566545344).

The spelling of 11213333214133 in words is "eleven trillion, two hundred thirteen billion, three hundred thirty-three million, two hundred fourteen thousand, one hundred thirty-three".