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112135424403 = 337378474801
BaseRepresentation
bin110100001101111001…
…0101100100110010011
3101201102220120202221210
41220123302230212103
53314123132040103
6123303031151203
711046551244402
oct1503362544623
9351386522853
10112135424403
1143613584072
1219895b15503
13a760a3ba42
1455daa51639
152db480ae03
hex1a1bcac993

112135424403 has 4 divisors (see below), whose sum is σ = 149513899208. Its totient is φ = 74756949600.

The previous prime is 112135424333. The next prime is 112135424411. The reversal of 112135424403 is 304424531211.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 112135424403 - 218 = 112135162259 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (112135424413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18689237398 + ... + 18689237403.

It is an arithmetic number, because the mean of its divisors is an integer number (37378474802).

Almost surely, 2112135424403 is an apocalyptic number.

112135424403 is a deficient number, since it is larger than the sum of its proper divisors (37378474805).

112135424403 is an equidigital number, since it uses as much as digits as its factorization.

112135424403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37378474804.

The product of its (nonzero) digits is 11520, while the sum is 30.

Adding to 112135424403 its reverse (304424531211), we get a palindrome (416559955614).

The spelling of 112135424403 in words is "one hundred twelve billion, one hundred thirty-five million, four hundred twenty-four thousand, four hundred three".

Divisors: 1 3 37378474801 112135424403