Base | Representation |
---|---|
bin | 1010001100101111011010… |
… | …1011111001100000011010 |
3 | 1110201001022011201000110022 |
4 | 2203023312223321200122 |
5 | 2432212234324023214 |
6 | 35503350401550442 |
7 | 2235120312461321 |
oct | 243136653714032 |
9 | 43631264630408 |
10 | 11214003345434 |
11 | 36339175a386a |
12 | 1311423045422 |
13 | 634625953a36 |
14 | 2aaa913610b8 |
15 | 146a7e1c2d8e |
hex | a32f6af981a |
11214003345434 has 16 divisors (see below), whose sum is σ = 16863278181120. Its totient is φ = 5592915881280.
The previous prime is 11214003345379. The next prime is 11214003345473. The reversal of 11214003345434 is 43454330041211.
It is a super-3 number, since 3×112140033454343 (a number of 40 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11214003345394 and 11214003345403.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2957207 + ... + 5583285.
It is an arithmetic number, because the mean of its divisors is an integer number (1053954886320).
Almost surely, 211214003345434 is an apocalyptic number.
11214003345434 is a deficient number, since it is larger than the sum of its proper divisors (5649274835686).
11214003345434 is a wasteful number, since it uses less digits than its factorization.
11214003345434 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2631445.
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 11214003345434 its reverse (43454330041211), we get a palindrome (54668333386645).
The spelling of 11214003345434 in words is "eleven trillion, two hundred fourteen billion, three million, three hundred forty-five thousand, four hundred thirty-four".
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