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11214003345434 = 243349312626079
BaseRepresentation
bin1010001100101111011010…
…1011111001100000011010
31110201001022011201000110022
42203023312223321200122
52432212234324023214
635503350401550442
72235120312461321
oct243136653714032
943631264630408
1011214003345434
1136339175a386a
121311423045422
13634625953a36
142aaa913610b8
15146a7e1c2d8e
hexa32f6af981a

11214003345434 has 16 divisors (see below), whose sum is σ = 16863278181120. Its totient is φ = 5592915881280.

The previous prime is 11214003345379. The next prime is 11214003345473. The reversal of 11214003345434 is 43454330041211.

It is a super-3 number, since 3×112140033454343 (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11214003345394 and 11214003345403.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2957207 + ... + 5583285.

It is an arithmetic number, because the mean of its divisors is an integer number (1053954886320).

Almost surely, 211214003345434 is an apocalyptic number.

11214003345434 is a deficient number, since it is larger than the sum of its proper divisors (5649274835686).

11214003345434 is a wasteful number, since it uses less digits than its factorization.

11214003345434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2631445.

The product of its (nonzero) digits is 69120, while the sum is 35.

Adding to 11214003345434 its reverse (43454330041211), we get a palindrome (54668333386645).

The spelling of 11214003345434 in words is "eleven trillion, two hundred fourteen billion, three million, three hundred forty-five thousand, four hundred thirty-four".

Divisors: 1 2 433 866 4931 9862 2135123 2626079 4270246 5252158 1137092207 2274184414 12949195549 25898391098 5607001672717 11214003345434