11214041014453 has 4 divisors (see below), whose sum is σ = 11214049079808. Its totient is φ = 11214032949100.

The previous prime is 11214041014447. The next prime is 11214041014471. The reversal of 11214041014453 is 35441014041211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 11214041014453 - 2¹³ = 11214041006261 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11214041014853) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1353973 + ... + 4925578.

It is an arithmetic number, because the mean of its divisors is an integer number (2803512269952).

Almost surely, 2^{11214041014453} is an apocalyptic number.

It is an amenable number.

11214041014453 is a deficient number, since it is larger than the sum of its proper divisors (8065355).

11214041014453 is an equidigital number, since it uses as much as digits as its factorization.

11214041014453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8065354.

The product of its (nonzero) digits is 7680, while the sum is 31.

Adding to 11214041014453 its reverse (35441014041211), we get a palindrome (46655055055664).

The spelling of 11214041014453 in words is "eleven trillion, two hundred fourteen billion, forty-one million, fourteen thousand, four hundred fifty-three".