1121413311331 has 4 divisors (see below), whose sum is σ = 1132300819312. Its totient is φ = 1110525803352.

The previous prime is 1121413311311. The next prime is 1121413311349. The reversal of 1121413311331 is 1331133141211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1121413311331 - 2⁵ = 1121413311299 is a prime.

It is a super-2 number, since 2×1121413311331² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1121413311296 and 1121413311305.

It is not an unprimeable number, because it can be changed into a prime (1121413311311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5443753836 + ... + 5443754041.

It is an arithmetic number, because the mean of its divisors is an integer number (283075204828).

Almost surely, 2^{1121413311331} is an apocalyptic number.

1121413311331 is a deficient number, since it is larger than the sum of its proper divisors (10887507981).

1121413311331 is a wasteful number, since it uses less digits than its factorization.

1121413311331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10887507980.

The product of its digits is 648, while the sum is 25.

Adding to 1121413311331 its reverse (1331133141211), we get a palindrome (2452546452542).

The spelling of 1121413311331 in words is "one trillion, one hundred twenty-one billion, four hundred thirteen million, three hundred eleven thousand, three hundred thirty-one".