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1121414433 = 3373804811
BaseRepresentation
bin100001011010111…
…0110110100100001
32220011010202101220
41002311312310201
54244040230213
6303135445253
736534602556
oct10265666441
92804122356
101121414433
11526011297
12273686829
1314b43ab49
14a8d14a2d
15686b5e23
hex42d76d21

1121414433 has 4 divisors (see below), whose sum is σ = 1495219248. Its totient is φ = 747609620.

The previous prime is 1121414431. The next prime is 1121414449. The reversal of 1121414433 is 3344141211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1121414433 - 21 = 1121414431 is a prime.

It is a super-2 number, since 2×11214144332 = 2515140661081422978, which contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1121414431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 186902403 + ... + 186902408.

It is an arithmetic number, because the mean of its divisors is an integer number (373804812).

Almost surely, 21121414433 is an apocalyptic number.

It is an amenable number.

1121414433 is a deficient number, since it is larger than the sum of its proper divisors (373804815).

1121414433 is an equidigital number, since it uses as much as digits as its factorization.

1121414433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 373804814.

The product of its digits is 1152, while the sum is 24.

The square root of 1121414433 is about 33487.5265285449. The cubic root of 1121414433 is about 1038.9358052183.

Adding to 1121414433 its reverse (3344141211), we get a palindrome (4465555644).

The spelling of 1121414433 in words is "one billion, one hundred twenty-one million, four hundred fourteen thousand, four hundred thirty-three".

Divisors: 1 3 373804811 1121414433