112142140563 has 4 divisors (see below), whose sum is σ = 149522854088. Its totient is φ = 74761427040.

The previous prime is 112142140507. The next prime is 112142140597. The reversal of 112142140563 is 365041241211.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 365041241211 = 3 ⋅121680413737.

It is not a de Polignac number, because 112142140563 - 2¹⁷ = 112142009491 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 112142140563.

It is not an unprimeable number, because it can be changed into a prime (112142140163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18690356758 + ... + 18690356763.

It is an arithmetic number, because the mean of its divisors is an integer number (37380713522).

Almost surely, 2^112142140563 is an apocalyptic number.

112142140563 is a deficient number, since it is larger than the sum of its proper divisors (37380713525).

112142140563 is an equidigital number, since it uses as much as digits as its factorization.

112142140563 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37380713524.

The product of its (nonzero) digits is 5760, while the sum is 30.

Adding to 112142140563 its reverse (365041241211), we get a palindrome (477183381774).

The spelling of 112142140563 in words is "one hundred twelve billion, one hundred forty-two million, one hundred forty thousand, five hundred sixty-three".