Base | Representation |
---|---|
bin | 11001011111111001101100… |
… | …001100111110101100010011 |
3 | 112201001210202011022122021220 |
4 | 121133321230030332230103 |
5 | 104144324201312043103 |
6 | 1034301545541420123 |
7 | 32423044164250410 |
oct | 3137715414765423 |
9 | 481053664278256 |
10 | 112143411440403 |
11 | 32806832204852 |
12 | 106b218970a643 |
13 | 4a761030c79b5 |
14 | 1d99aad127107 |
15 | ce7192b78c53 |
hex | 65fe6c33eb13 |
112143411440403 has 32 divisors (see below), whose sum is σ = 177162204022272. Its totient is φ = 61765734316800.
The previous prime is 112143411440353. The next prime is 112143411440419. The reversal of 112143411440403 is 304044114341211.
It is not a de Polignac number, because 112143411440403 - 210 = 112143411439379 is a prime.
It is a super-2 number, since 2×1121434114404032 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (112143411540403) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 784554228 + ... + 784697153.
It is an arithmetic number, because the mean of its divisors is an integer number (5536318875696).
Almost surely, 2112143411440403 is an apocalyptic number.
112143411440403 is a deficient number, since it is larger than the sum of its proper divisors (65018792581869).
112143411440403 is a wasteful number, since it uses less digits than its factorization.
112143411440403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1569251515.
The product of its (nonzero) digits is 18432, while the sum is 33.
Adding to 112143411440403 its reverse (304044114341211), we get a palindrome (416187525781614).
The spelling of 112143411440403 in words is "one hundred twelve trillion, one hundred forty-three billion, four hundred eleven million, four hundred forty thousand, four hundred three".
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