112145125213333 has 4 divisors (see below), whose sum is σ = 112158525284460. Its totient is φ = 112131725142208.

The previous prime is 112145125213259. The next prime is 112145125213339. The reversal of 112145125213333 is 333312521541211.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 39029594432689 + 73115530780644 = 6247367^2 + 8550762^2 .

It is a cyclic number.

It is not a de Polignac number, because 112145125213333 - 2³³ = 112136535278741 is a prime.

It is a super-2 number, since 2×112145125213333² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 112145125213292 and 112145125213301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (112145125213339) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6700023010 + ... + 6700039747.

It is an arithmetic number, because the mean of its divisors is an integer number (28039631321115).

Almost surely, 2^{112145125213333} is an apocalyptic number.

It is an amenable number.

112145125213333 is a deficient number, since it is larger than the sum of its proper divisors (13400071127).

112145125213333 is an equidigital number, since it uses as much as digits as its factorization.

112145125213333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13400071126.

The product of its digits is 64800, while the sum is 37.

Adding to 112145125213333 its reverse (333312521541211), we get a palindrome (445457646754544).

The spelling of 112145125213333 in words is "one hundred twelve trillion, one hundred forty-five billion, one hundred twenty-five million, two hundred thirteen thousand, three hundred thirty-three".