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11215151113 = 59190087307
BaseRepresentation
bin10100111000111100…
…11010000000001001
31001221121021201002011
422130132122000021
5140432034313423
65052511335521
7544631132365
oct123436320011
931847251064
1011215151113
11483572a031
12220bb215a1
131099687cba
147856b82a5
154598dcb0d
hex29c79a009

11215151113 has 4 divisors (see below), whose sum is σ = 11405238480. Its totient is φ = 11025063748.

The previous prime is 11215151053. The next prime is 11215151117. The reversal of 11215151113 is 31115151211.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31115151211 = 81138366401.

It is a cyclic number.

It is not a de Polignac number, because 11215151113 - 229 = 10678280201 is a prime.

It is a super-2 number, since 2×112151511132 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11215151117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95043595 + ... + 95043712.

It is an arithmetic number, because the mean of its divisors is an integer number (2851309620).

Almost surely, 211215151113 is an apocalyptic number.

It is an amenable number.

11215151113 is a deficient number, since it is larger than the sum of its proper divisors (190087367).

11215151113 is an equidigital number, since it uses as much as digits as its factorization.

11215151113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 190087366.

The product of its digits is 150, while the sum is 22.

The spelling of 11215151113 in words is "eleven billion, two hundred fifteen million, one hundred fifty-one thousand, one hundred thirteen".

Divisors: 1 59 190087307 11215151113