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1122022112003 = 1386309393231
BaseRepresentation
bin10000010100111101101…
…110101011101100000011
310222021010122112222011122
4100110331232223230003
5121340400130041003
62215241055502455
7144030516406502
oct20247556535403
93867118488148
101122022112003
113a293525a761
12161556b27a2b
1381a6339ca90
143c440162839
151e2bdeeb238
hex1053dbabb03

1122022112003 has 4 divisors (see below), whose sum is σ = 1208331505248. Its totient is φ = 1035712718760.

The previous prime is 1122022111997. The next prime is 1122022112083. The reversal of 1122022112003 is 3002112202211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1122022112003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1122022112083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43154696603 + ... + 43154696628.

It is an arithmetic number, because the mean of its divisors is an integer number (302082876312).

Almost surely, 21122022112003 is an apocalyptic number.

1122022112003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1122022112003 is a deficient number, since it is larger than the sum of its proper divisors (86309393245).

1122022112003 is an equidigital number, since it uses as much as digits as its factorization.

1122022112003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 86309393244.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 1122022112003 its reverse (3002112202211), we get a palindrome (4124134314214).

The spelling of 1122022112003 in words is "one trillion, one hundred twenty-two billion, twenty-two million, one hundred twelve thousand, three".

Divisors: 1 13 86309393231 1122022112003