Base | Representation |
---|---|
bin | 110100001111111001… |
… | …0010001110010001001 |
3 | 101201121120122200100100 |
4 | 1220133302101302021 |
5 | 3314242310022213 |
6 | 123313423200013 |
7 | 11051323602012 |
oct | 1503762216211 |
9 | 351546580310 |
10 | 112202423433 |
11 | 43648385471 |
12 | 198b4446009 |
13 | a771899639 |
14 | 56058d2009 |
15 | 2dba642773 |
hex | 1a1fc91c89 |
112202423433 has 48 divisors (see below), whose sum is σ = 174042086400. Its totient is φ = 69446976480.
The previous prime is 112202423387. The next prime is 112202423477. The reversal of 112202423433 is 334324202211.
112202423433 is a `hidden beast` number, since 1 + 1 + 2 + 202 + 4 + 23 + 433 = 666.
It is not a de Polignac number, because 112202423433 - 218 = 112202161289 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 112202423397 and 112202423406.
It is not an unprimeable number, because it can be changed into a prime (112202423483) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1999878 + ... + 2055216.
It is an arithmetic number, because the mean of its divisors is an integer number (3625876800).
Almost surely, 2112202423433 is an apocalyptic number.
It is an amenable number.
112202423433 is a deficient number, since it is larger than the sum of its proper divisors (61839662967).
112202423433 is a wasteful number, since it uses less digits than its factorization.
112202423433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55602 (or 55599 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 112202423433 its reverse (334324202211), we get a palindrome (446526625644).
The spelling of 112202423433 in words is "one hundred twelve billion, two hundred two million, four hundred twenty-three thousand, four hundred thirty-three".
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