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11221212113 = 15174312663
BaseRepresentation
bin10100111001101011…
…00001101111010001
31001222000200122012122
422130311201233101
5140440112241423
65053245304025
7545033505056
oct123465415721
931860618178
1011221212113
114839099821
122211b65015
13109a9ca9a7
1478641502d
1545a1d88c8
hex29cd61bd1

11221212113 has 4 divisors (see below), whose sum is σ = 11295524928. Its totient is φ = 11146899300.

The previous prime is 11221212097. The next prime is 11221212131. The reversal of 11221212113 is 31121212211.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31121212211 = 57753936243.

It is a cyclic number.

It is not a de Polignac number, because 11221212113 - 24 = 11221212097 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11221212091 and 11221212100.

It is not an unprimeable number, because it can be changed into a prime (11221212143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37156181 + ... + 37156482.

It is an arithmetic number, because the mean of its divisors is an integer number (2823881232).

Almost surely, 211221212113 is an apocalyptic number.

It is an amenable number.

11221212113 is a deficient number, since it is larger than the sum of its proper divisors (74312815).

11221212113 is an equidigital number, since it uses as much as digits as its factorization.

11221212113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 74312814.

The product of its digits is 48, while the sum is 17.

Adding to 11221212113 its reverse (31121212211), we get a palindrome (42342424324).

The spelling of 11221212113 in words is "eleven billion, two hundred twenty-one million, two hundred twelve thousand, one hundred thirteen".

Divisors: 1 151 74312663 11221212113