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11221300103 = 13863176931
BaseRepresentation
bin10100111001101011…
…10111001110000111
31001222000212002220112
422130311313032013
5140440123100403
65053251223235
7545034322436
oct123465671607
931860762815
1011221300103
114839149942
122211ba7b1b
13109aa2ba60
1478643911d
1545a2049d8
hex29cd77387

11221300103 has 4 divisors (see below), whose sum is σ = 12084477048. Its totient is φ = 10358123160.

The previous prime is 11221299997. The next prime is 11221300159. The reversal of 11221300103 is 30100312211.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30100312211 = 197152793463.

It is a cyclic number.

It is not a de Polignac number, because 11221300103 - 210 = 11221299079 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11221300163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 431588453 + ... + 431588478.

It is an arithmetic number, because the mean of its divisors is an integer number (3021119262).

Almost surely, 211221300103 is an apocalyptic number.

11221300103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

11221300103 is a deficient number, since it is larger than the sum of its proper divisors (863176945).

11221300103 is an equidigital number, since it uses as much as digits as its factorization.

11221300103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 863176944.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 11221300103 its reverse (30100312211), we get a palindrome (41321612314).

The spelling of 11221300103 in words is "eleven billion, two hundred twenty-one million, three hundred thousand, one hundred three".

Divisors: 1 13 863176931 11221300103